JEE PYQ: Rotational Motion Question 21
Question 21 - 2020 (03 Sep Shift 1)
Moment of inertia of a cylinder of mass $M$, length $L$ and radius $R$ about an axis passing through its centre and perpendicular to the axis of the cylinder is $I = M\left(\frac{R^2}{4} + \frac{L^2}{12}\right)$. If such a cylinder is to be made for a given mass of a material, the ratio $L/R$ for it to have minimum possible $I$ is:
(1) $\frac{2}{3}$
(2) $\frac{3}{2}$
(3) $\sqrt{\frac{3}{2}}$
(4) $\sqrt{\frac{2}{3}}$
BETA
