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JEE PYQ: Rotational Motion Question 22

Question 22 - 2020 (03 Sep Shift 1)

A block of mass $m = 1$ kg slides with velocity $v = 6$ m/s on a frictionless horizontal surface and collides with a uniform vertical rod and sticks to it as shown. The rod is pivoted about $O$ and swings as a result of the collision making angle $\theta$ before momentarily coming to rest. If the rod has mass $M = 2$ kg, and length $l = 1$ m, the value of $\theta$ is approximately: (take $g = 10$ m/s$^2$)

Rod pivoted at O at top, block of mass m collides at bottom of rod with velocity v. Rod swings to angle $\theta$

(1) 63$°$

(2) 55$°$

(3) 69$°$

(4) 49$°$

Show Answer

Answer: (1)


Learning Progress: Step 22 of 70 in this series