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JEE PYQ: Rotational Motion Question 32

Question 32 - 2020 (06 Sep Shift 1)

Shown in the figure is a hollow ice-cream cone (it is open at the top). If its mass is $M$, radius of its top, $R$ and height, $H$, then its moment of inertia about its axis is:

Hollow cone, open at top, with radius R at top and height H

(1) $\frac{MR^2}{2}$

(2) $\frac{M(R^2 + H^2)}{4}$

(3) $\frac{MH^2}{3}$

(4) $\frac{MR^2}{3}$

Show Answer

Answer: (4)


Learning Progress: Step 32 of 70 in this series