JEE PYQ: Rotational Motion Question 32
Question 32 - 2020 (06 Sep Shift 1)
Shown in the figure is a hollow ice-cream cone (it is open at the top). If its mass is $M$, radius of its top, $R$ and height, $H$, then its moment of inertia about its axis is:
(1) $\frac{MR^2}{2}$
(2) $\frac{M(R^2 + H^2)}{4}$
(3) $\frac{MH^2}{3}$
(4) $\frac{MR^2}{3}$