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JEE PYQ: Rotational Motion Question 37

Question 37 - 2020 (07 Jan Shift 2)

Mass per unit area of a circular disc of radius $a$ depends on the distance $r$ from its centre as $\sigma(r) = A + Br$. The moment of inertia of the disc about the axis, perpendicular to the plane and passing through its centre is:

(1) $2\pi a^4\left(\frac{A}{4} + \frac{aB}{5}\right)$

(2) $2\pi a^4\left(\frac{aA}{4} + \frac{B}{5}\right)$

(3) $\pi a^4\left(\frac{A}{4} + \frac{aB}{5}\right)$

(4) $2\pi a^4\left(\frac{A}{4} + \frac{B}{5}\right)$

Show Answer

Answer: (1)


Learning Progress: Step 37 of 70 in this series