JEE PYQ: Rotational Motion Question 38
Question 38 - 2020 (08 Jan Shift 1)
A particle of mass $m$ is fixed to one end of a light spring having force constant $k$ and unstretched length $l$. The other end is fixed. The system is given an angular speed $\omega$ about the fixed end of the spring such that it rotates in a circle in gravity free space. Then the stretch in the spring is:
(1) $\frac{ml\omega^2}{k - \omega m}$
(2) $\frac{ml\omega^2}{k - m\omega^2}$
(3) $\frac{ml\omega^2}{k + m\omega^2}$
(4) $\frac{ml\omega^2}{k + m\omega}$
BETA
