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JEE PYQ: Rotational Motion Question 56

Question 56 - 2019 (12 Apr Shift 1)

A circular disc of radius $b$ has a hole of radius $a$ at its centre (see figure). If the mass per unit area of the disc varies as $\left(\frac{\sigma_0}{r}\right)$, then the radius of gyration of the disc about its axis passing through the centre is:

Annular disc with inner radius $a$ and outer radius $b$

(1) $\sqrt{\frac{a^2 + b^2 + ab}{2}}$

(2) $\frac{a + b}{2}$

(3) $\sqrt{\frac{a^2 + b^2 + ab}{3}}$

(4) $\frac{a + b}{3}$

Show Answer

Answer: (1)


Learning Progress: Step 56 of 70 in this series