JEE PYQ: Rotational Motion Question 57
Question 57 - 2019 (12 Apr Shift 2)
A smooth wire of length $2\pi r$ is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating with angular speed $\omega$ about the vertical diameter AB, as shown in figure, the bead is at rest with respect to the circular ring at position P as shown. Then the value of $\omega^2$ is equal to:
(1) $\frac{\sqrt{3}g}{2r}$
(2) $2g/(r\sqrt{3})$
(3) $(g\sqrt{3})/r$
(4) $2g/r$