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JEE PYQ: Rotational Motion Question 57

Question 57 - 2019 (12 Apr Shift 2)

A smooth wire of length $2\pi r$ is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating with angular speed $\omega$ about the vertical diameter AB, as shown in figure, the bead is at rest with respect to the circular ring at position P as shown. Then the value of $\omega^2$ is equal to:

Circle rotating about vertical diameter AB, bead at position P at angle from center, radius r/2 from axis

(1) $\frac{\sqrt{3}g}{2r}$

(2) $2g/(r\sqrt{3})$

(3) $(g\sqrt{3})/r$

(4) $2g/r$

Show Answer

Answer: (2)


Learning Progress: Step 57 of 70 in this series