JEE PYQ: Semiconductors Question 33
Question 33 - 2019 (10 Apr 2019 Shift 1)
An npn transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance is $100\ \Omega$ and the output load resistance is $10\ \text{k}\Omega$. The common emitter current gain $\beta$ is:
(1) $10^2$
(2) 60
(3) $6 \times 10^2$
(4) $10^4$
Show Answer
Answer: (1)
Solution
$60 = 10\log(P_0/P_i)$, so $P_0/P_i = 10^6 = \beta^2(10000/100)$. $\beta^2 = 10^4$, $\beta = 100$.
BETA
