JEE PYQ: Semiconductors Question 34
Question 34 - 2019 (10 Apr 2019 Shift 1)
A message signal of frequency 100 MHz and peak voltage 100 V is used to execute amplitude modulation on a carrier wave of frequency 300 GHz and peak voltage 400 V. The modulation index and difference between the two side band frequencies are:
(1) $4$; $1 \times 10^8$ Hz
(2) $4$; $2 \times 10^8$ Hz
(3) $0.25$; $2 \times 10^8$ Hz
(4) $0.25$; $1 \times 10^{-8}$ T
Show Answer
Answer: (3)
Solution
Bandwidth $= 2f_m = 2 \times 10^8$ Hz. Modulation index $= A_m/A_c = 100/400 = 0.25$.
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