JEE PYQ: Thermal Properties Of Matter Question 10
Question 10 - 2020 (09 Jan 2020 Shift 2)
Starting at temperature 300 K, one mole of an ideal diatomic gas ($\gamma = 1.4$) is first compressed adiabatically from volume $V_1$ to $V_2 = \frac{V_1}{16}$. It is then allowed to expand isobarically to volume $2V_2$. If all the processes are the quasi-static then the final temperature of the gas (in °K) is (to the nearest integer) ____.
Show Answer
Answer: 1818
Solution
Adiabatic: $T_2 = 300 \times (16)^{0.4}$. Isobaric: $T_f = 2T_2 = 300 \times 2 \times (16)^{0.4} = 1818$ K
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