JEE PYQ: Thermal Properties Of Matter Question 8
Question 8 - 2020 (08 Jan 2020 Shift 2)
A Carnot engine having an efficiency of $\frac{1}{10}$ is being used as a refrigerator. If the work done on the refrigerator is 10 J, the amount of heat absorbed from the reservoir at lower temperature is:
(1) 99 J
(2) 100 J
(3) 1 J
(4) 90 J
Show Answer
Answer: (4)
Solution
$\frac{1}{10} = \frac{W}{Q_1} \Rightarrow Q_1 = 100$ J. $Q_2 = Q_1 - W = 100 - 10 = 90$ J
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