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JEE PYQ: Thermodynamics Question 15

Question 15 - 2020 (03 Sep Shift 1)

A balloon filled with helium (32$°$C and 1.7 atm.) bursts. Immediately afterwards the expansion of helium can be considered as :

(1) irreversible isothermal

(2) irreversible adiabatic

(3) reversible adiabatic

(4) reversible isothermal

Show Answer

Answer: (2)

Solution

Bursting of helium balloon is irreversible and in this process $\Delta Q = 0$, so adiabatic.


Learning Progress: Step 15 of 45 in this series