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In SI unit the dimensions of $\sqrt{\frac{\varepsilon_0}{\mu_0}}$ is:
(1) $A^{-1}T , ML^3$
(2) $AT^2 M^{-1}L^{-1}$
(3) $AT^{-3}ML^{3/2}$
(4) $A^2T^3 M^{-1} L^{-2}$
$\sqrt{\frac{\varepsilon_0}{\mu_0}} = \varepsilon_0 \cdot c$. Working through the dimensions of $\varepsilon_0$ and $c$ gives $[M^{-1}L^{-2}T^3A^2]$.
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