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If speed (V), acceleration (A) and force (F) are considered as fundamental units, the dimension of Young’s modulus will be:
(1) $V^{-2}A^2F^{-2}$
(2) $V^{-2}A^2F^2$
(3) $V^{-4}A^{-2}F$
(4) $V^{-4}A^2F$
Let $[Y] = [V]^a [F]^b [A]^c$. Comparing dimensions: $b = 1, a = -4, c = 2$. So $[Y] = [V^{-4}A^2F]$.
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