JEE PYQ: Units And Dimensions Question 6
Question 6 - 2020 (02 Sep Shift 1)
If speed $V$, area $A$ and force $F$ are chosen as fundamental units, then the dimension of Young’s modulus will be:
(1) $FA^2V^{-1}$
(2) $FA^2V^{-3}$
(3) $FA^2V^{-2}$
(4) $FA^{-1}V^0$
Show Answer
Answer: (4)
Solution
Young’s modulus $Y = \frac{\text{stress}}{\text{strain}} = \frac{F/A}{\Delta l/l_0} = FA^{-1}V^0$.