JEE PYQ: Wave Optics Question 14
Question 14 - 2020 (04 Sep Shift 2)
Orange light of wavelength $6000 \times 10^{-10}$ m illuminates a single slit of width $0.6 \times 10^{-4}$ m. The maximum possible number of diffraction minima produced on both sides of the central maximum is __________.
Show Answer
Answer: 198
Solution
For obtaining secondary minima at a point, path difference should be integral multiple of wavelength.
$\therefore d\sin\theta = n\lambda$
$\therefore \sin\theta = \frac{n\lambda}{d}$
For $n$ to be maximum $\sin\theta = 1$
$n = \frac{d}{\lambda} = \frac{6 \times 10^{-5}}{6 \times 10^{-7}} = 100$
Total number of minima on one side = 99
Total number of minima = 198.
BETA
