JEE PYQ: Wave Optics Question 2
Question 2 - 2021 (18 Mar Shift 1)
In Young’s double slit arrangement, slits are separated by a gap of 0.5 mm, and the screen is placed at a distance of 0.5 m from them. The distance between the first and the third bright fringe formed when the slits are illuminated by a monochromatic light of $5890$ $\AA$ is :-
(1) $1178 \times 10^{-9}$ m
(2) $1178 \times 10^{-6}$ m
(3) $1178 \times 10^{-12}$ m
(4) $5890 \times 10^{-7}$ m
Show Answer
Answer: (2)
Solution
$\beta = \frac{\lambda D}{d} = \frac{5890 \times 10^{-10} \times 0.5}{0.5 \times 10^{-3}}$
$= 589 \times 10^{-6}$ m
Distance between first and third bright fringe is $2\beta = 2 \times 589 \times 10^{-6}$ m
$= 1178 \times 10^{-6}$ m
BETA
