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JEE PYQ: Wave Optics Question 32

Question 32 - 2019 (09 Jan Shift 1)

Two coherent sources produce waves of different intensities which interfere. After interference, the ratio of the maximum intensity to the minimum intensity is 16. The intensity of the waves are in the ratio:

(1) 16 : 9

(2) 25 : 9

(3) 4 : 1

(4) 5 : 3

Show Answer

Answer: (2)

Solution

As we know, $\frac{I_{\max}}{I_{\min}} = \left(\frac{A_1 + A_2}{A_1 - A_2}\right)^2$

and $\sqrt{\frac{I_1}{I_2}} = \frac{A_1}{A_2}$

$\frac{I_{\max}}{I_{\min}} = 16 \Rightarrow \frac{A_{\max}}{A_{\min}} = 4 \Rightarrow \frac{A_1 + A_2}{A_1 - A_2} = \frac{4}{1}$

Using componendo and dividendo:

$\frac{A_1}{A_2} = \frac{5}{3} \Rightarrow \frac{I_1}{I_2} = \left(\frac{5}{3}\right)^2 = \frac{25}{9}$


Learning Progress: Step 32 of 38 in this series