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JEE PYQ: Waves And Sound Question 1

Question 1 - 2021 (16 Mar Shift 2)

A closed organ pipe of length L and an open organ pipe contain gases of densities $\rho_1$ and $\rho_2$ respectively. The compressibility of gases are equal in both the pipes. Both the pipes are vibrating in their first overtone with same frequency. The length of the open pipe is $\frac{x}{3}L\sqrt{\frac{\rho_1}{\rho_2}}$ where $x$ is __________. (Round off to the Nearest Integer)

Show Answer

Answer: 4

Solution

$f_c = f_o$

$\frac{3V_c}{4L} = \frac{2V_o}{2L’}$

$\frac{3V_c}{4L} = \frac{V_o}{L’}$

$L’ = \frac{4L}{3} \cdot \frac{V_o}{V_c} = \frac{4L}{3}\sqrt{\frac{B/\rho_1}{B/\rho_2}}$ (B is bulk modulus)

$= \frac{4L}{3}\sqrt{\frac{\rho_1}{\rho_2}}$

$x = 4$


Learning Progress: Step 1 of 47 in this series