JEE PYQ: Waves And Sound Question 14
Question 14 - 2020 (05 Sep Shift 1)
In a resonance tube experiment when the tube is filled with water up to a height of 17.0 cm from bottom, it resonates with a given tuning fork. When the water level is raised the next resonance with the same tuning fork occurs at a height of 24.5 cm. If the velocity of sound in air is 330 m/s, the tuning fork frequency is :
(1) 2200 Hz
(2) 550 Hz
(3) 1100 Hz
(4) 3300 Hz
Show Answer
Answer: (1)
Solution
Here, $l_1 = 17$ cm and $l_2 = 24.5$ cm, $V = 330$ m/s, $f = ?$
$\lambda = 2(l_2 - l_1) = 2 \times (24.5 - 17) = 15$ cm
Now, from $v = f\lambda \Rightarrow 330 = \lambda \times 15 \times 10^{-2}$
$\therefore \lambda = \frac{330}{15} \times 100 = \frac{1100 \times 100}{5} = 2200$ Hz
BETA
