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JEE PYQ: Waves And Sound Question 28

Question 28 - 2019 (09 Apr Shift 2)

A string 2.0 m long and fixed at its ends is driven by a 240 Hz vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is:

(1) 180 m/s, 80 Hz

(2) 320 m/s, 80 Hz

(3) 320 m/s, 120 Hz

(4) 180 m/s, 120 Hz

Show Answer

Answer: (2)

Solution

$\frac{3\lambda}{2} = 2$ or $\lambda = \frac{4}{3}$ m

Velocity, $v = f\lambda = 240 \times \frac{4}{3} = 320$ m/sec

Also $f_1 = \frac{240}{3} = 80$ Hz


Learning Progress: Step 28 of 47 in this series