A) $ -C\equiv N $
B) $ -S{O_3}H $
C) $ -COOH $
D) $ -N{O_2} $
ಸರಿಯಾದ ಉತ್ತರ: D
ಕೊಡುಗೆಗಳ ನಿರ್ವಹಿಸುವ ತೀವ್ರತೆಯ ಕ್ರಮ
$ -NO _2>-SO _3H>-C\equiv N>-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}},-OH $
ಆದ್ದರಿಂದ, ? $ NO _2 $ ಅತ್ಯಂತ ನಿರ್ವಹಿಸುವ ಉಪಸಂಹಾರ.
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