प्रकरण १० पदार्थाचे औष्णिक गुणधर्म
उत्तर आणि समाधान $$ \begin{equation*} \frac{t_{F}-32}{180}=\frac{t_{C}}{100} \tag{10.1} \end{equation*} $$ आहे.
BETA
The Ministry of Education has launched the SATHEE initiative in association with IIT Kanpur to provide free guidance for competitive exams. SATHEE offers a range of resources, including reference video lectures, mock tests, and other resources to support your preparation. Please note that participation in the SATHEE program does not guarantee clearing any exam or admission to any institute.