A) 25
B) 75
C) 60
D) 50
योग्य उत्तर: B
डी-ब्रॉग्ली तरंगलांबीसाठी $ {\lambda_1}\frac{h}{p}=\frac{h}{\sqrt{2mK}}, $ .(i)
$ {\lambda_2}=\frac{h}{\sqrt{2m16K}}=\frac{h}{4\sqrt{2mK}}=\frac{{\lambda_1}}{4} $ (ii)
$ {\lambda_2}=$25%,of,${\lambda_1} $ तरंगलांबीत 75% बदल होतो.
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