[1994]
(a) $CH_3 CH(OH)_2$
(b) $ClCH_2 CH(OH)_2$
(c) $(CH_3)_2 C(OH)_2$
(d) $CCl_3 CH(OH)_2$.
Correct Answer: 8.(d)
Solution:
(d) Due to-I-effect of the three $C-Cl$-bonding between $Cl$ and $C$-atom of the $OH$ group, $CCl_3$ $CH(OH)_2$ is most stable.
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