Coordination Compounds Ques 23

23. Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test of chloride ions with silver nitrate at $25^{\circ} C$ ?

[2015]

(a) $CoCl_3 \cdot 4 NH_3$

(b) $CoCl_3 \cdot 5 NH_3$

(c) $CoCl_3 \cdot 6 NH_3$

(d) $CoCl_3 \cdot 3 NH_3$

Show Answer

Solution:

  1. (d) $CoCl_3 \cdot 3 NH_3$ will not give test for chloride ions with silver nitrate due to absence of ionisable chloride atoms.

$CoCl_3 \cdot 3 NH_3 \Rightarrow[Co(NH_3)_3 Cl_3]$

$[Co(NH_3)_3 Cl_3] \xrightarrow{AgNO_3}$ noppt

Secondary valence is fixed for a metal/ion. For $Co^{3+}$, it is six.



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