Coordination Compounds Ques 59
59. The $d$ electron configurations of $Cr^{2+}, Mn^{2+}, Fe^{2+}$ and $Ni^{2+}$ are $3 d^{4}, 3 d^{5}, 3 d^{6}$ and $3 d^{8}$ respectively. Which one of the following aqua complexes will exhibit the minimum paramagnetic behaviour?
[2007]
(a) $[Fe(H_2 O)_6]^{2+}$
(b) $[Ni(H_2 O)_6]^{2+}$
(c) $[Cr(H_2 O)_6]^{2+}$
(d) $[Mn(H_2 O)_6]^{2+}$
(At. No. $Cr=24, Mn=25, Fe=26, Ni=28$ )
Show Answer
Answer:
Correct Answer: 59.(b)
Solution:
(b) Lesser is the number of unpaired electrons smaller will be the paramagnetic behaviour. As $Cr^{2+}, Mn^{2+}, Fe^{2+} & Ni^{2+}$ contains.
As $Ni^{2+}$ has minimum no. of unpaired $e^{-}$thus this is least paramagnetic.
BETA
