Coordination Compounds Ques 61
61. An excess of $\mathrm{AgNO}_3$ is added to $100 $ $\mathrm{~mL}$ of a $0.01 $ $\mathrm{M}$ solution of dichlorotetraaquachromium $(III)$ chloride. The number of moles of $\mathrm{AgCl}$ precipitated would be :
[NEET 2013]
(a) $0.002$
(b) $0.003$
(c) $0.01$
(d) $0.001$
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Answer:
Correct Answer: 61.(d)
Solution: (d)
$ \left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl}+\mathrm{AgNO}_3 \longrightarrow \mathrm{AgCl}+ $ $ {\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right] \mathrm{NO}_3} $
$ \text { Molarity }=\frac{\text { wt }}{\text { mol. mass }} \times \frac{1000}{\text { vol. }} $
$ \frac{\mathrm{wt}}{\mathrm{mol} \text { mass }}=\text { molarity } \times \frac{\text { vol. }}{1000}=\frac{0.01 \times 100}{1000} $
$ =0.001 $
BETA
