Electrochemistry Ques 33
33. A solution contains $Fe^{2+}, Fe^{3+}$ and $I^{-}$ions. This solution was treated with iodine at $35^{\circ} C$. $E^{\circ}$ for $Fe^{3+} / Fe^{2+}$ is $+0.77 V$ and $E^{\circ}$ for $I_2 / 2 I^{-}=0.536 V$. The favourable redox reaction is :
[2011 M]
(a) $I_2$ will be reduced to $I^{-}$
(b) There will be no redox reaction
(c) $I^{-}$will be oxidised to $I_2$
(d) $Fe^{2+}$ will be oxidised to $Fe^{3+}$
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Answer:
Correct Answer: 33.(c)
Solution:
(c) Given $Fe^{+3} / Fe^{2+}=+0.77 V$
and $I_2 / 2 I^{-}=0.536 V$
Reduction potential of $Fe^{3+} / Fe^{2+}>I_2 / I^{-}$, so $Fe^{3+}$ will be reduced and $I^{-}$will be oxidised.
BETA
