Electrochemistry Ques 41
41. If $E _{Fe^{2+} / Fe}^{\circ}=-0.441 V$ and $E _{Fe^{\circ} / Fe^{2+}}$ $=+0.771 V$, the standard EMF of the reaction $Fe+2 Fe^{3+} \to 3 Fe^{2+}$ will be
[2006]
(a) $1.653 V$
(b) $1.212 V$
(c) $0.111 V$
(d) $0.330 V$
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Answer:
Correct Answer: 41.(b)
Solution:
(b)
$Fe \longrightarrow Fe^{2+}+2 e^{-} \quad$ [Anode] $\quad E=-0.441 V$
$[Fe^{3+}+e^{-} \longrightarrow Fe^{2+}] \times 2 \text{ [Cathode] } E=+0.771 V$
${Fe+2 Fe^{3+} \longrightarrow 3 Fe^{2+}}$
$E _{\text{cell }}^{o}=E _{\text{cathode }}^{o}-E _{\text{Anode }}^{o}$
$=0.771-(-0.441)=0.771+0.441=1.212 V$