Electrochemistry Ques 41

41. If $E _{Fe^{2+} / Fe}^{\circ}=-0.441 V$ and $E _{Fe^{\circ} / Fe^{2+}}$ $=+0.771 V$, the standard EMF of the reaction $Fe+2 Fe^{3+} \to 3 Fe^{2+}$ will be

[2006]

(a) $1.653 V$

(b) $1.212 V$

(c) $0.111 V$

(d) $0.330 V$

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Answer:

Correct Answer: 41.(b)

Solution:

(b)

$Fe \longrightarrow Fe^{2+}+2 e^{-} \quad$ [Anode] $\quad E=-0.441 V$

$[Fe^{3+}+e^{-} \longrightarrow Fe^{2+}] \times 2 \text{ [Cathode] } E=+0.771 V$

${Fe+2 Fe^{3+} \longrightarrow 3 Fe^{2+}}$

$E _{\text{cell }}^{o}=E _{\text{cathode }}^{o}-E _{\text{Anode }}^{o}$

$=0.771-(-0.441)=0.771+0.441=1.212 V$