Equilibrium Ques 26
26. The equilibrium constant for the reaction $A_2 \rightarrow 2 A$ at $500 K$ and $700 K$ are $1 \times 10^{-10}$ and $1 \times 10^{-5}$ respectively. The given reaction is
[1996]
(a) exothermic
(b) slow
(c) endothermic
(d) fast
Show Answer
Solution:
- (b) $A_2 \rightarrow 2 A$ Equilibrium constant is given by $K_c=\frac{[A]^{2}}{[A_2]}$
Since the value given is very small, hence concentration of products is less. It means the reaction is slow.
BETA
