[2000]
(a) $NH_4^{+}$
(b) $NH_3$
(c) $NH_2$
(d) $NH$
Correct Answer: 53.(b)
Solution:
$NH_3+H_2 O \rightleftharpoons NH_2^{-}+H_3 O^{+}$
(Conjugate acid-base pair differ only by a proton)
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