Equilibrium Ques 57
57. The $pH$ value of a $10$ $ M$ solution of $HCl$ is
[1995]
(a) less than $0$
(b) equal to $0$
(c) equal to $1$
(d) equal to $2$
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Answer:
Correct Answer: 57.(a)
Solution:
- (a) Molarity $(M)=10 M$. $HCl$ is a strong acid and it is completely dissociated in aqueous solutions as : $HCl(10) \rightleftharpoons H^{+}(10)+Cl^{-}$.
So, for every moles of $HCl$, there is one $H^{+}$.
Therefore $[H^{+}]=[HCl]$ or $[H^{+}]=10$.
$pH=-\log [H^{+}]=-\log [10]=-1$.
BETA
