Equilibrium Ques 69
69. Concentration of the $Ag^{+}$ions in a saturated solution of $Ag_2 C_2 O_4$ is $2.2 \times 10^{-4}$ $ mol $ $L^{-1}$. Solubility product of $Ag_2 C_2 O_4$ is :-
[2017]
(a) $2.66 \times 10^{-12}$
(b) $4.5 \times 10^{-11}$
(c) $5.3 \times 10^{-12}$
(d) $2.42 \times 10^{-8}$
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Answer:
Correct Answer: 69.(c)
Solution:
- (c) $Ag_2 C_2 O_4(s) \rightleftharpoons \underset{2 s}{2 Ag^{+}}(aq)+C_2 O_4^{2-}(aq) $
$K _{s p}=[Ag^{+}]^{2}[C_2 O_4^{2-}]$
$[Ag^{+}]=2.2 \times 10^{-4} M$
Given that:
$\therefore$ Concentration of $C_2 O_4{ }^{2-}$ ions,
$ [C_2 O_4^{2-}]=\frac{2.2 \times 10^{-4}}{2} M=1.1 \times 10^{-4} M $
$\therefore K _{s p} =(2.2 \times 10^{-4})^{2}(1.1 \times 10^{-4}) $
$ =5.324 \times 10^{-12}$
BETA
