Equilibrium Ques 9

9. Value of $K_P$ in the reaction

$MgCO_3(s) \to MgO(s)+CO_2(g)$ is

[2000]

(a) $K_P=P _{CO_2}$

(b) $K_P=P _{CO_2} \times \frac{P _{CO_2} \times P _{MgO}}{P _{MgCO_3}}$

(c) $K_P=\frac{P _{CO_2} \times P _{MgO}}{P _{MgCO_3}}$

(d) $K_P=\frac{P _{MgCO_3}}{P _{CO_2} \times P _{MgO}}$

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Answer:

Correct Answer: 9.(a)

Solution:

  1. (a) $MgCO_3$ (s) $\rightarrow MgO$ (s) $+CO_2$ (g)

$MgO$ & $MgCO_3$ are solid and they do not exert any pressure and hence only pressure exerted is by $CO_2$. Therefore $K_P=P _{CO 2}$