[2001]
(a) $1.7 \times 10^{-16}$
(b) $1.7 \times 10^{-6}$
(c) $1.7 \times 10^{-18}$
(d) $1.7 \times 10^{-12}$
(a) $M_2 S \rightarrow \underset{2 s}{2 M^{+}}+\underset{s}{S^{–}}$
Solubility product $=(2 s)^{2}(s)=4 s^{3}$
$=4(3.5 \times 10^{-6})^{3}=1.7 \times 10^{-16}$
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