[2002]
(a) $CH_3-CH=CH_2$
(b) $CH_3-C \equiv CH$
(c)
(d)
Correct Answer: 16.(b)
Solution:
(b) $CH_3-CH_2-CHCl_2 \xrightarrow[\Delta]{NaNH_2}$
$CH_3-CH=CHCl \xrightarrow[\Delta]{NaNH_2} \underset{\text{ Final Product }}{CH_3-C \equiv CH}$
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