Hydrocarbons Ques 32
32. A hydrocarbon ‘$A$’ on chlorination gives ‘$B$’ which on heating with alcoholic potassium hydroxide changes into another hydrocarbon ‘$C$’. The latter decolourises Baeyer’s reagent and on ozonolysis forms formaldehyde only. ‘$A$’ is
[1998]
(a) Ethane
(b) Butane
(c) Methane
(d) Ethene
Show Answer
Answer:
Correct Answer: 32.(a)
Solution:
- (a) Since hydrocarbon $C$ gives only $CH_2 O$, on ozonolysis, $C$ should be $CH_2=CH_2$, Hence going backward, A should be ethane. Thus, the reactions are
BETA
