$CH_2=CH_2 \xrightarrow[\text{ acid }]{\text{ Hypochlorous }} CH_2OH \xrightarrow{R} \underset{CH_2 OH}{CH_2 OH}$
molecule ’ $M$ ’ and reagent ’ $R$ ’ are respectively
[1997]
(a) $CH_3 CH_2 Cl$ and $NaOH$
(b) $CH_3 CH_2 OH$ and $H_2 SO_4$
(c) $CH_2 Cl-CH_2 OH$ and aqueous $NaHCO_3$
(d) $CH_2CH_2$ and heat
Correct Answer: 33.(c)
Solution:
$M=CH_2OH-CH_2Cl$ and $R=NaHCO_3$
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