Nuclear Chemistry Ques 15
15. Number of neutrons in a parent nucleus $X$, which gives $ _7^{14} N$ nucleus, after two successive $\beta$ decays, would be
[1998]
9
6
7
8
Show Answer
Solution:
- (a) $ _5 X^{14} \xrightarrow{-\beta} _7 Y^{14} \xrightarrow{-\beta} _8 N^{14}$
No. of neutrons $=$ Mass number - No. of proton $=14-5=9$
BETA
