Nuclear Chemistry Ques 9
9. A nuclide of an alkaline earth metal undergoe radioactive decay by emission of the $\alpha$-particle: in succession. The group of the periodic table, to which the resulting daughter element wouk belong is
$[2005]$
(a) $Gr. 4$
(b) $Gr. 6$
(c) $Gr. 14$
(d) $Gr. 16$
Show Answer
Answer:
Correct Answer: 9.(c)
Solution:
- (c) When $IIA$ group element $(Ra)$ emits one $\alpha$-particle its group no. decreases by two unit. i.e., go into zero group $(Gr. 16)$ But as it is radioactive thus due to successive emission last product is $Pb$ i.e., $(Gr.14).$
BETA
