Nuclear Chemistry Ques 9
9. A nuclide of an alkaline earth metal undergoes radioactive decay by emission of the $\alpha$-particle: in succession. The group of the periodic table, to which the resulting daughter element would belong is
$[2005]$
(a) $Gr. 4$
(b) $6th Grade$
(c) $Gr. 14$
(d) $Gr. 16$
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Answer:
Correct Answer: 9.(c)
Solution:
When $IIA$ group element $(Ra)$ emits one $\alpha$-particle its group no. decreases by two unit. i.e., go into zero group $(Gr. 18)$ But as it is radioactive thus due to successive emission last product is $Pb$ i.e., $(Gr.14).$
BETA
