Organic Chemistry Some Basic Principles And Techniques Ques 15
15. A straight chain hydrocarbon has the molecular formula $C_8 H _{10}$. The hybridization of the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$. The structural formula of the hydrocarbon would be :
[1991]
(a) $CH_3 C \equiv CCH_2-CH=CHCH=CH_2$
(b) $CH_3 CH_2-CH=CHCH=CHC \equiv CH$
(c) $CH_3 CH=CHCH_2-C \equiv CCH=CH_2$
(d) $CH_3 CH=CHCH_2-CH=CH-C \equiv CH$.
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Answer:
Correct Answer: 15.(d)
Solution:
- (d) $CH_3 CH=CHCH_2-CH=CH-C \equiv CH$.
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