Organic Chemistry Some Basic Principles And Techniques Ques 68
68. In the hydrocarbon
$ \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH} $
$6 \quad \quad \quad 5 \quad \quad 4 \quad \quad 3 \quad \quad 2 \quad \quad 1$
The state of hybrization of carbons $1,3$ and $5$ are in the following sequence:
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(a) $s p^2, s p, s p^3$
(b) $s p, s p^3, s p^2$
(c) $s p, s p^2, s p^3$
(d) $s p^3, s p^2, s p$
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Answer:
Correct Answer: 68.(b)
Solution: (b) $\mathrm{C}-1$ is $s p$ hybridized $(\mathrm{C} \equiv \mathrm{C})$
$\mathrm{C}-3$ is $s p^3$ hybridized $(\mathrm{C}-\mathrm{C})$
$\mathrm{C}-5$ is $s p^2$ hybridized $(\mathrm{C}=\mathrm{C})$
Thus the correct sequence is $s p, s p^3, s p^2$.
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