Periodic Classification And Periodic Properties Ques 10
10. Which of the following has the maximum number of unpaired electrons?
(a) $\mathrm{Mg}^{2+}$
(b) $\mathrm{Ti}^{3+}$
(c) $\mathrm{V}^{3+}$
(d) $\mathrm{Fe}^{2+}$
$(1996,1 \mathrm{M})$
Show Answer
Answer:
Correct Answer: 10.(b)
Solution:
- $\mathrm{Mg}^{2+}=1 s^{2} 2 s^{2} 2 p^{6}=$ no unpaired electron
$\mathrm{Ti}^{3+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{1}=$ one unpaired electron
$\mathrm{V}^{3+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{2}=$ two unpaired electrons
$\mathrm{Fe}^{2+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{6}=$ four unpaired electrons
BETA
