Redox Reactions Ques 5
5. For the redox reaction
[2018]
$MnO_4^{-}+C_2 O_4^{2-}+H^{+} \to Mn^{2+}+CO_2+H_2 O$
The correct coefficients of the reactants for the balanced equation are
$MnO_4^{-} \quad C_2 O_4^{2-} \quad H^{+}$ $
(a) $ 16 \quad \quad 5 \quad \quad \quad 2 $
(b) $ 2 \quad \quad 5 \quad \quad \quad 16 $
(c) $ 5 \quad \quad 16 \quad \quad \quad 2 $
(d) $ 2 \quad \quad 16 \quad \quad \quad 5 $
Show Answer
Answer:
Correct Answer: 5.(b)
Solution:
Multiplying (i) by 2 and (ii) by 5 to balance $e^{-}$
$ 2 MnO_4^{-}+5 C_2 O_4^{2-} \longrightarrow 2 Mn^{2+}+10 CO_2 $
On balancing charge;
$ 2 MnO_4^{-}+5 C_2 O_4^{2-}+ 16 H^{+} \longrightarrow$ $ 2 Mn^{2+}+10 CO_2+8 H_2 O$
BETA
