(a) $Sc^{3+}$
(c) $Ti^{3+}$
(b) $V^{3+}$
(d) $Cr^{3+}$
[2000]
$ Ti^{+3} \to[Ar]^{18} 3 d^{1} ; Cr^{+3} \to[Ar]^{18} 3 d^{3} $
Scandium ion doesn’t contain any unpaired electron in d orbitals hence it forms colourless compound.
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