(At. nos, $Ni=28, Ti=22, Cr=24, Co=27$ ) [2015]
(a) $Ti^{3+}$
(b) $Cr^{2+}$
(c) $Co^{2+}$
(d) $Ni^{2+}$
Number of unpaired electrons $(n)=2$
Hence, $Ni^{2+}$ gives magnetic moment of 2.84 B.M.
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