The D And F Block Elements Ques 42
42. $KMnO_4$ can be prepared from $K_2 MnO_4$ as per the reaction: $2K_2MnO_4 + Cl_2 \rightarrow 2KMnO_4 + 2KCl$
$3 MnO_4^{2-} + 2 H_2O \rightarrow$
$ 2 MnO_4^{-} + MnO_2 + 4 OH^{-} $
The reaction can go to completion by removing $OH^{-}$ ions by adding.
[NEET 2013]
(a) $KOH$
(b) $CO_2$
(c) $SO_2$
(d) $HCl$
Show Answer
Solution:
$HCl$ and $SO_2$ are reducing agents and can reduce $MnO_4^{-}$. $CO_2$, which is neither oxidising nor reducing, will provide only acidic medium. It can shift the reaction in the forward direction and the reaction can go to completion.
BETA
