The P Block Elements Ques 94
94. Identify the incorrect statement, regarding the molecule $XeO_4$ :
(a) $XeO_4$ molecule is tetrahedral
[NEET Kar. 2013]
(b) $XeO_4$ molecule is square planar
(c) There are four $p \pi-d \pi$ bonds
(d) There are four $s p^{3}-p, \sigma$ bonds
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Solution:
- (b)
OW(O)(O)O
(Tetrahedral $s p^{3}$ )
$Xe$ : Ground state
$[Kr] 4 d^{10} 5 s^{2} 5 p^{6} 5 d^{0}$
$Xe:$ Excited state
$4 s p^{3}$ hybridised orbitals form 4 sigma bond with oxygen.
BETA
