[2019]
(a) $Sr(OH)_2$
(b) $Ca(OH)_2$
(c) $Mg(OH)_2$
(d) $Be(OH)_2$
Correct Answer: 17.(d)
Solution:
(d) Amphoteric hydroxide means it can react with both acid and base.
$Be(OH)_2+2 HCl \longrightarrow BeCl_2+2 H_2 O$
$Be(OH)_2+2 NaOH \longrightarrow Na_2[Be(OH)_4]$
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